500 2500.
100 times because if you do the opposite with the numbers you have, 500/5=100
100 + 300 + 500 + 500 + 600 = 2000. Then divide by 5 to get 400. The mean of these five numbers is 400.
Multiply by 5 4*5 = 20 20*5 = 100 100*5 = 500 500*5 = 2500
0.8
There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.
Never mind guys I figured it out!
200, 500 and 201.
100 times because if you do the opposite with the numbers you have, 500/5=100
500
40. There are 400 numbers between 100 and 500 and one in every ten ends in 5.
100 + 300 + 500 + 500 + 600 = 2000. Then divide by 5 to get 400. The mean of these five numbers is 400.
Well First, you need 500 because 500/5 is obviuosly 100. 98+99+100+101+102= 500. Therefore, the consecutive whole numbers are 98,99,100,101,102! -Levizy123
The 3 digit numbers under 500 are 100 through 499.
500
Multiply by 5 4*5 = 20 20*5 = 100 100*5 = 500 500*5 = 2500
500
There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.