Sixteen and Thirty Two
the next three numbers are 180 540 and 1620=)
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
The pattern is multiply by -1, add 5, repeat. The next three numbers are: -7, -2, 2
Should there be a 16 in there somewhere? If so next three are 36, 49 and 64...
1/5 , 1/25 , 1/125
64, 125 and 216
What numbers would you like to be the next three? It is possible to find a polynomial of order 5 that will fit these three numbers and ANY other three numbers. For example, using the positin to value rule given by Un= -112.275n5 + 1,966.25n4 - 12,744.625n3 + 37,416.25n2 - 48,979.6 + 36,525 I can fit the numbers 1, 2 and 3 as the next three. So there are infinitely many possible answers to the question. Using the simplest rule, although the question does not require that, gives Un = 70n + 2001 and that requires the next three numbers to be 2281, 2351, 2421.
1 0 0.5 0 0
41 122 365
12, 13, 16 Add three, then add 1, then add three, then add 1, and so on so forth
Those are the powers of 2, separated by digits. In other words, 1, 2, 4, 8, 16, ... where each number is twice the previous one ... so the next three numbers are 1 2 8.
Seems like each number is obtained by adding 3 to the previous number. Hence the next three numbers are 13, 16, 19