t(n) = 3n-1 , where n = 1, 2, 3, ...
t(5) = 81
t(6) = 243
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
1 & 27; 3 & 9.
The LCM of the given two numbers is 27
1 and 27 3 and 9
The difference between the numbers is increasing by 1 every time. Therefore, since the difference between the last two numbers is equal to 6, the difference between the next two numbers will be 7. 20 + 7 = 27. Therefore the next number in the sequence will be 27.
6,13,27,55, 111, 223 ... Here is why: 6 + (1x7) makes 13 13 + (2x7) makes 27 27 + (4x7) makes 55 55 + (8x7) makes 111 111 + (16x7) makes 223 Or this way explains the answer using powers of 2: (7x20)-1 makes 6 (7x21)-1 makes 13 (7x22)-1 makes 27 (7x23)-1 makes 55 (7x24)-1 makes 111 (7x25)-1 makes 223
1 and 0
81, 243, 729 The numbers are being multiplied by 3.
1 x 27, 3 x 9
1 x 27, 3 x 9
1 and 27 do.
1 x 27 3 x 9