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What are the odds of getting five blacks in a row on the roulett table?
Techen
In American roulette there are 18 black pockets on the wheel, 18 red pockets, a "0" pocket and a "00" pocket. So there are 38 pockets in total. This makes the probability of getting a black on a single spin 18/38=0.474 (i.e. about 47.4%).
The probability of getting five blacks in a row is therefore (0.474)5=0.0238 (2.4%).
The odds (ratio of probable success to failure) of getting five blacks is therefore (1-0.0238)/0.238 or roughly 41 to 1 against.
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