It you mean two 8 in a row then it's (1/8)2 = 1/64 as the probability to get 8 is 1/8
Suppose A is the event {rolling a 6-sided die 20 times and getting a 5} Then A', the complement of A, is the event {rolling a 6-sided die 20 times and not getting a 5 any times} So Pr(A) = 1 - Pr(A') = 1 - (5/6)20 = 1 - 0.026084 = 0.973916 (to 6 dp)
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
It depends on how many times you throw it! On a single throw, the answer is 0.5
1 in 6 times 1 in 6 equals 1 in 36
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
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One half, 1:2, 1/2, etc...
Suppose A is the event {rolling a 6-sided die 20 times and getting a 5} Then A', the complement of A, is the event {rolling a 6-sided die 20 times and not getting a 5 any times} So Pr(A) = 1 - Pr(A') = 1 - (5/6)20 = 1 - 0.026084 = 0.973916 (to 6 dp)
i am not sure
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
It depends on how many times you throw it! On a single throw, the answer is 0.5
1 in 6 times 1 in 6 equals 1 in 36
It is approx 0.1445
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
1/4? ...
The number of times that an image is reflected in a six sided snowflake is infinity. It is easy to construct a six sided snowflake in a PC.
The probability of getting an even sum on two dice is 18 in 36 or 1 in 2 or 0.5. The probability of doing that three times in a row is 0.53 or 0.125.