0
What else can I help you with?
What is the probability of getting a least one tail when tossing eight fair coins?
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
If you were to flip a coin 4 times what is the probability of getting heads at least one time?
As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.
What is the probability of obtaining exactly seven heads in eight flips of a coin given that at least one is a head?
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
Toss a coin 3 times and what is the probability of getting at least two heads?
There are 23 or 8 possible outcomes listed below (H=Head, T=Tails). HHH HHT HTH HTT THH THT TTH TTT each has a 1/8 probability. Count the number that has at least 2 heads and it is 3. So, the probability is 3/8.
On an eight question true false quiz a student guesses each answer What is the probability that he gets at least One of the answers correct?
The probability of getting at least 1 answer correct = 1 - Probability of getting all answers correct.So in your case it for be P(at least 1 answer correct) = 1 - 1/256where 256 is your sample space, |S| = 2^8.
What is the probability of getting a least one tail when tossing eight fair coins?
The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
If you were to flip a coin 6 times what is the probability of you getting at least four heads?
To calculate the probability of getting at least four heads when flipping a coin six times, we can use the binomial probability formula. The total number of outcomes for six flips is (2^6 = 64). The probabilities for getting exactly four, five, and six heads can be calculated using the binomial formula, and their sum gives the total probability of getting at least four heads. This results in a probability of approximately 0.65625, or 65.625%.
If you were to flip a coin 4 times what is the probability of getting heads at least one time?
As the question is "what is the probability of getting at least one head" the correct way to answer this is to ask what is the probability of not getting any heads and then subtract this from 1.The probability of not getting a head in 4 flips = 0.54 (i.e. 0.5 * 0.5 * 0.5 * 0.5) = 1/16.Therefore the probability of getting at least one head is 1 - 1/16 = 15/16.
What is the probability of getting at least 2 heads when flipping a coin 3 times?
.125
Suppose six coins are flipped then the probality of getting at least one tail?
The probability of getting at least one tail in a flip of six coins is the same as the probability of not getting all heads, which is 1 - (0.56), or 0.984375.
What is the probability of obtaining exactly seven heads in eight flips of a coin given that at least one is a head?
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
What is the probability of getting heads at least once if a fair coin is flipped three times?
7/8
What is the probability of getting heads more than once if you flip a coin three times?
For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times
What is the probability of showing at least one head from 4 coin tosses?
To find the probability of getting at least one head in 4 coin tosses, it's easier to calculate the complementary probability of getting no heads at all (i.e., getting all tails). The probability of getting tails in a single toss is 0.5, so for 4 tosses, the probability of all tails is ( (0.5)^4 = 0.0625 ). Therefore, the probability of getting at least one head is ( 1 - 0.0625 = 0.9375 ) or 93.75%.
When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
What is the probability of tossing a coin 9 times and getting at least one tail?
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
What is the probability of rolling a six sided number cube eight times and getting at least five three's?
00
