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What are the possible values of x y and z when 2x plus 3y plus 5z equals 0.7 showing correctly worked out examples?
Wiki User
∙ 7y ago
If: 2x+3y+5z = 0.7
Then let 0.7 be the numerators of three fractions and their denominators be three times the coefficient of the variables:-
So: 2*(0.7/6)+3*(0.7/9)+5*(0.7/15) = 0.7
Therefore: x = 0.7/6, y = 0.7/9 and z = 0.7/15
Or: x = 7/60, y = 7/90 and z = 7/150
Wiki User
∙ 7y ago
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