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What are the prime factors of -216?

Anonymous

∙ 12y ago

Updated: 8/19/2019

The prime factorization of 216 is 2,2,2,3,3,3 or 2 x 2 x 2 x 3 x 3 x 3.

Prime factorization is finding prime numbers that multiplies together to satisfy the product. In your case, the product is 216.

Wiki User

∙ 14y ago

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More answers

2 x 2 x 2 x 3 x 3 x 3 = 216 The prime factors of 216 are 2 and 3.

Wiki User

∙ 14y ago

2 and 3

Wiki User

∙ 12y ago

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Related Questions

What is the prime factor for 216?

216 has two prime factors: 2 and 3.

Which prime numbers equal 216?

The prime factors of 216 are: 2, 3

What is the sum of the prime factors of 216-1?

217

Is 54 a prime of 216?

54 is not a prime; its prime factors ar 2x33. The prime factors of 216 are 23x33, and all the factors of 216 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 27, 36, 54, 72, 108, and 216.

What is the primary factor of 216?

The prime factors of 216 are 2 and 3.

What is 216 expressed in prime numbers?

As a product of its prime factors expressed in exponents it is: 23*33 = 216

Prime factorization of 216?

The prime factors for 216 are 2,2,2,3,3, and 3. 2 x 2 x 2 x 3 x 3 x 3 = 216

What is a distinct factor?

All numbers (except for 1 and 0) have prime factors. Sometimes the prime factors are repeated. The prime factorization of 216 is 2 x 2 x 2 x 3 x 3 x 3. The distinct prime factors of 216 are 2 and 3.

What is the prime factors of 216 and write as a power?

2^3 x 3^3

What is a prime power factorization?

All composite numbers can be expressed as unique products of prime numbers. This is accomplished by dividing the original number and its factors by prime numbers until all the factors are prime. A factor tree can help you visualize this. Example: 216 216 Divide by two. 108,2 Divide by two. 54,2,2 Divide by two. 27,2,2,2 Divide by three. 9,3,2,2,2 Divide by three. 3,3,3,2,2,2 Stop. All the factors are prime. 2 x 2 x 2 x 3 x 3 x 3 = 216 Repeated factors can be abbreviated by the use of exponents (powers). 23 x 33 = 216 That's the prime power factorization of 216.

What is the smallest number whose factors are cubes of two different prime numbers?

2 and 3 are the smallest prime numbers. So answer is 2^3 * 3^3 = 216

What is 6 cubed in expontentional form?

It is 216 and as a product of its prime factors in exponents: 2^3*3^3 = 216

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