2^2 x 3 x 5^2 x 7
2*2*3*5*5*7 = 2100 or as 22*3*52*7 = 2100
No, all even numbers greater than two are composite.
As a product of its prime factors in exponents it is: 22*3*52*7 = 2100
To find two numbers that multiply to 2100, we need to factorize 2100. The prime factorization of 2100 is 2^2 * 3 * 5^2 * 7. To find two numbers, we can pair up these prime factors - for example, 2 * 1050, 3 * 700, 5 * 420, or 6 * 350. Therefore, the pairs of numbers that multiply to 2100 are (2, 1050), (3, 700), (5, 420), and (6, 350).
2,100 is a Composite Number.
2100
2100
composite
In Roman numerals, 2100 is represented as MMC.
4x3x25x7 is not a prime factorization because 25 and 4 not are prime numbers. We can write 25 as 5x5 = 52 and 4 as 2x2 = 22. Rewriting again the given expression as: 22x3x52x7, on simplifying we get 2100.
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2100 = 2 * 2 * 3 * 5 * 5 * 7 = 22 * 3 * 52 * 7