I do not believe that there are any rational roots.
3x3=99+2=1111+3=14=14
what kind of polynomial is shown 3x3+x+1
3x3+12x = 3x(x2+4)
if its 3x3 - 2x + 1 then its a cubic trinomial
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
12
One-houndred and thirty five.
3x
12x6 - 16x3 - 15x3 + 20 = 4x3(3x3 - 4) - 5(3x3 - 4) = (3x3 - 4)(4x3 - 5)
the answer to this is 4x + 57 (assuming that the 4x in the question is algebra)
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- 3X3 + X2 + 17 + 6X4Three. I will put the coefficients in parentheses.(- 3 )X3 + (1)X2 + 17 + (6)X4=========================( remember, 1 is always an implied coefficient )