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-1/2x2 - 1/2x + 6 = 5
Multiply by -2 : x2 + x - 12 = - 10 or x2 + x - 2 = 0
Factorising: (x + 2)(x - 1) = 0
So x + 2 = 0 or x - 1 = 0
therefore, x = -2 or x = 1
x = 2 and x = -5
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
Only one: (3,-2)
2.
There's only one solution. [ x = -7 ]
2
It has 2 solutions and they are x = 2 and y = 1 which are applicable to both equations
It has two equal solutions for x which are x = 2 and x = 2
x = 2 and x = -5
no if 1 plus 1 equals 2 then 2 plus 2 equals 4.
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
Only one: (3,-2)
There's only one solution. [ x = -7 ]
2.
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
2x - y = 8 x + y = 1 These are your two equations. They will have two solutions since you have two variables. The solutions are x=3 and y=-2
It has 2 real solutions because the discriminant is greater than zero.