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If: kx+y = 4 and y = x^2 +8

Then: x^2 +8 = 4-kx or x^2 +8 -4+kx = 0 => x^2+4+kx = 0

The discriminant of the above quadratic equation must equal 0

So: k^2 -4*(4*1) = 0 => k^2-16 = 0

Therefore: k^2 = 16 and so the values of k are -4 and +4

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Q: What are the values of k when kx plus y equals 4 is a tangent to the curve of y equals x squared plus 8 on the Cartesian plane showing work?
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