I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
(6,0) and (0,2)
"y = 2x2 - 12x + 6" is a quadratic equation which describes a parabola whose vertex occurs at the point (3, -12) and which has a range of -12 → ∞. It intercepts the x-axis at the points (3 - √6, 0) and (3 + √6, 0).
12
-12 +/- sq root 104
-5 + (-4) - 12 - 20 - (-10) + 6 = -25
12 - 78 + 2397543 - 124 + 3 = 2397356
8 plus 4 minus 12 divided by 1 is 0.
18 + 12 + 0 - 4 - 10 = 16
10 - 5 + 14324 + 12 + 30 - 1000 = 13371
y2-12=5x is an equation. When graphed, it is a parabola.
Negative 12 minus 3 plus 9 is equal to -6