31, 32, 33
31 32 33
They are -32, -31 and -30.
The numbers are 31, 32 and 33.
-30 -31 -32
31, 32 and 33
-31, -32, -33
32+33+34=99
-30,-31,-32
The integers are 15 and 17.
That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.
Average is 96/3 ie 32 so integers are 30, 32 and 34.