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Q: What are three consecutive integers for the sum of 32?

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31, 32, 33

31 32 33

They are -32, -31 and -30.

The numbers are 31, 32 and 33.

-30 -31 -32

31, 32 and 33

-31, -32, -33

32+33+34=99

-30,-31,-32

The integers are 15 and 17.

That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.

Average is 96/3 ie 32 so integers are 30, 32 and 34.

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