Q: What are three consecutive numbers whose sum is 132?

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The numbers are -134, -132 and -130.

3 consecutive even integers whose sum is 396 are 130, 132 and 134.

42, 44, 46.

42, 44, 46.

It is not possible in our Universe that two consecutive numbers can total an even number, since any two consecutive numbers must be an odd and an even (or vice versa). There are two consecutive odd numbers which total 132 ie 65 and 67

108, 120, 132

132, 156 and 204

How about: 127+5 = 132

131 and 133

12 and 66

43, 44, 45

11 & 12 are the integers whose product is 132.

The numbers are 65 and 67.

11 and 12

132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.

LCM(11, 12) = 132 so the numbers are 132, 132*2 and 132*3.

11 and 12

The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132

127, 3 and 2

Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.

Since 13 is not an even number, a list of even numbers cannot start with 13. Perhaps you mean 3 consecutive even numbers greater than 13: 14, 16, 18. Or perhaps you mean 3 consecutive even numbers starting with the digits 1 and 3: 130, 132, 134.

The LCM of the given three numbers is 3036

The LCM of the given three numbers is 3036

134

They are: 11 times 12 = 132

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