They are: 11 times 12 = 132
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
66 X 2=132
How about: 127+5 = 132
The product of two numbers is the answer to multiplying the two numbers together.
They are: 11 times 12 = 132
11 and 12
132 = 11 x 12 ie 11 x 3 x 2 x 2 . the answer is there are no two prime numbers whose product is 132.
as 132 is an even number at least one of the two numbers must also be even 12 + 11 = 23 12 x 11 = 132
The LCM of 132 and 136 is 4488. The LCM of a pair is the product of the two numbers divided by their GCF. Since the difference between the two numbers is four, we know that the GCF cannot be larger than four. Four divides evenly into both numbers, so it is the GCF. 132 * 136 / 4 = 4488.
11, 12 -11, -12
66 X 2=132
How about: 127+5 = 132
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
The product of two numbers is the answer to multiplying the two numbers together.
113 + 19 = 132 109 + 23 = 132 103 + 29 = 132 101 + 31 = 132 89 + 43 = 132 79 + 53 = 132 73 + 59 = 132 71 + 61 = 132 So there are 8 pairs of prime numbers that sum to 132.
The LCM of two numbers is sometimes the product of the two numbers.