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Q: What are three factors that has the numbers 2 4 and 8?

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The common factors of the three numbers are 1, 2, and 4.

The numbers are: 8 16 and 24

12 and 24

All composite numbers have more than two factors. The smallest such number is 4, which is equal to 2 x 2. 4 has three factors: 1, 2, and 4.

Three factors

8, 88, 808808088 are three examples.

1, 2 and 4

8, 16 and 24

They are: 8, 16 and 24

What two numbers have the factors 2 4 and 8

1, 2, 4 are the factors of 4.

Every multiple of 4 has 2 and 4 as factors.

Four only has three factors: 1, 2 and 4. For any of them to be a GCF, they need to be compared to another set of numbers.

Calculate the least common multiple of the three numbers. Any multiple of that has all those numbers as factors.

Numbers that have 2 factors are prime numbers; Numbers that have 4 factors are either: * the cube of a prime; or * the product of two different primes; Numbers that have 8 factors are either: * a prime to the power 7; * the product of a prime cubed and different prime; * the product of three different primes.

Three. The common factors are: 1, 2, 4.

1200, 12600 and 12660001200 are three numbers.

48, 4800 and 484848 are three possibilities.

4, with factors 1, 2 and 4

These numbers have 2 and 4 as factors: 4, 8,16, 20, 28, 32, 36, 40. Any multiple of 4.

You can find the prime factors of all three numbers, combine (multiply) those numbers and remove redundant factors. So if your numbers are 4, 6 and 8, then those factors are (2*2), (3*2), and (2*2*2) respectively. The GCF is 24 or (2*2*2*3). This is because 24 can be written as a multiple of all three numbers because 24 can be written as a multiple of 2 4 and 6. (2*2*3*(2)) (2*3*(4)) and (2*2*(6)). If this is still unclear you can check the Wikipedia Article on LCM.

4

Numbers with three factors are squares of primes. So: 4, 9, 25

1 and 2 are factors of both numbers.

The prime factors of 140 are 2, 2, 5, and 7. The prime factors of 124 are 2, 2, and 31. The prime factors of 152 are 2, 2, 2, and 19. The only common factors are 2 and 2. Include 1, and you find that the three numbers that will evenly go into 140, 124, and 152 are 1, 2, and 4.