Pick any two numbers. Call them a and b. Then calculate 42 - a - b, to get the third number.
This means that the question has an infinite number of solutions. Here are some solutions:
0 + 0 + 42
0 + 1 + 41
1 + 1 + 40
(-1) + (-1) + 44
i + 2i + (42-3i)
1/2 + 1/2 + 41
Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
12
The numbers are 40, 41 and 42.
The numbers are 41, 42 and 43.
12+14+16 = 42
37, 3, 2
The only way for three prime numbers to have a sum of 42 is if one of the prime numbers is 2, as 2 is the only even prime number. The other two prime numbers must add up to 40, which can only be achieved by 3 and 37. Therefore, the three prime numbers that have a sum of 42 are 2, 3, and 37.
The numbers are 38, 40 and 42.
The numbers are 41, 42 and 43.
41, 42, 43
41+42+43 = 126
14 and 21 have a sum of 35 and an LCM of 42