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Q: What are three prime numbers that equal 56?

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no

They are: 2+11+43 = 56

56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

They are: 2*2*2*7 = 56

The prime numbers (factors) of 56 are: 2 and 7

The prime numbers (factors) of 56 are: 2 and 7

No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56

56, 84, 112

53+3 and 43+13 and 47+9

Yes it can be divided by 1,7 and 8

56=2x2x2x7

Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.

Two and seven: 2 x 2 x 2 x 7 = 56

No, 56 can be divided by 2 to equal 28.

53 and 3 are two prime numbers that add up to 56

To get the gcf of 56 and 48, you have to split the numbers into their prime factors: 56 = 2x2x2x7 48 = 2x2x2x2x3 Next you have to spot any common prime factors. In this case both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 And so the GCF of 56 and 48 is 8.

To find the prime numbers of 56, start with two numbers that when multiplied together equal 56. For example: 2 x 28 = 56. Two is prime, but 28 is composite, so it needs to be factored. 2 x 2 x 14 = 56. Now, 14 is prime, so factor it. 2 x 2 x 2 x 7 = 56. All the factors are now prime, so the prime factors are 2 x 2 x 2 x 7.

56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.

7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.

7 x 8 = 58 When you factor that into prime factors: 7 x 2 x 4 7 x 2 x 2 x 2 you get the four prime numbers that equal 56.

The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.

None of those four numbers are prime numbers.

Two of them.

2, 3 and 73

As a product of its prime factors: 2*2*2*7 = 56