56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
56 does not have only three prime factors.
No because as a product of its prime factors: 2*2*2*7 = 56
As a product of its prime factors: 2*2*2*7 = 56
As a product of its prime factors in exponents: 26*56 = 1,000,000
One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
56, 84, 112
56 = 2 x 2x 2 x 7 56 = 23 x 7
Yes it can be divided by 1,7 and 8