56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56
No because as a product of its prime factors: 2*2*2*7 = 56
As a product of its prime factors: 2*2*2*7 = 56
As a product of its prime factors in exponents: 26*56 = 1,000,000
One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...
Well, darling, you're out of luck on this one. Prime numbers are only divisible by 1 and themselves, so there's no way to add three of them together to get 56. You might want to brush up on your math facts before trying to stump me next time.
The prime numbers (factors) of 56 are: 2 and 7
The prime numbers (factors) of 56 are: 2 and 7
56, 84, 112
56 = 2 x 2x 2 x 7 56 = 23 x 7
Yes it can be divided by 1,7 and 8