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Q: Is 56 a product of three prime numbers?

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56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56

56 does not have only three prime factors.

No because as a product of its prime factors: 2*2*2*7 = 56

As a product of its prime factors: 2*2*2*7 = 56

As a product of its prime factors in exponents: 26*56 = 1,000,000

One number has to be 7, because that is a prime factor of 56. The other two numbers must total 8 and multiply to 8. Can't be done...

56 = 2 x 2 x 2 x 7

The prime numbers (factors) of 56 are: 2 and 7

The prime numbers (factors) of 56 are: 2 and 7

56, 84, 112

56 = 2 x 2x 2 x 7 56 = 23 x 7

Yes it can be divided by 1,7 and 8

56=2x2x2x7

Numbers cannot "make" another number prime. If you are looking for the prime factorization of 56, it is 23 * 7.

53 and 3 are two prime numbers that add up to 56

As a product of its prime factors: 2*3*7 = 42 As a product of its prime factors: 2*2*2*7 = 56

To get the gcf of 56 and 48, you have to split the numbers into their prime factors: 56 = 2x2x2x7 48 = 2x2x2x2x3 Next you have to spot any common prime factors. In this case both numbers have three 2s as prime factors. Multiply these together and you get: 2x2x2 = 8 And so the GCF of 56 and 48 is 8.

As a product of its prime factors: 2*2*2*5 = 40 As a product of its prime factors: 2*2*2*7 = 56 As a product of its prime factors: 3*13 = 39

56 and 84 are both composite numbers, so neither are prime and they are not relatively prime either as they share several factors.

The prime factorization of 56 is 2, 2, 2, and 7, so there there are two prime numbers, 2 and 7, that can evenly go into 56.

None of those four numbers are prime numbers.

Two of them.

2, 3 and 73

As a product of its prime factors: 2*2*2*2 = 16 As a product of its prime factors: 2*2*2*7 = 56