by making them half
The 3-digit counting numbers are 100 through 999 = 900 numbers.Half them are multiples of 2 (even numbers).The other half are not . . . 450 of them.
I think the answer is 612!1 (tens digit) which is odd is half of 2 (hundreds digit) and the sum is (6+1+2=9).
The first 5 digit number is 10,000 and the last is 99,999. Thus there are 90,000 numbers between that range. Half of them are odd & half are even. 45,000 each
There are 899 three digit numbers (100 through 999).Each century (grouping of 100 numbers) has 50 odd numbers. (half of the numbers are odd, half are even)So.. 100-199, 200-299, 300-399, 400-499, 500-599, 600-699, 700-799, 800-899, 900-999We have 9 centuries.Number of odd numbers = 9*50 = 450
4082 Since the tens digit is 2 times the thousand digit, it must be an even digit. So it can be 8, 6, 4, or 2. But, the thousands digit is 4 greater than the hundred digit. So that the hundred digit must be 0, the thousands digit must be 4, the hundreds digit must be 8, and the ones digit must be 2.
Half of them. Every other number from 0 to 99998 is even. Since there are 90,000 five digit numbers, that means that 45,000 of them are even.
You can have a box shape, with sides that have a length of any three numbers, as long as the product of these three numbers is one half.
Even numbers are divisible by two, and half of all numbers are even, so there is a 50 percent chance that a four-digit number is divisible by two.
Half of the last digit = 0.05 poundsHalf of the last digit = 0.05 poundsHalf of the last digit = 0.05 poundsHalf of the last digit = 0.05 pounds
blank in a half
8, 11, and 20.
Not at all. Six times one half is three, and one half is not an integer.
33 is an odd number because the last digit is a three making it odd. The short answer: Any number is even or odd based on the last digit at the end of the number. The boring long answer: Between 0 and 9 there are five odd numbers and five even numbers the odd numbers would be 1, 3, 5, 7, 9 the even numbers would be 0, 2, 4, 6, 8 Even numbers can evenly be divided in half, for example: 8 divided in half is 4. Odd numbers can not be evenly divided in half, for example: 9 divided in half is 4.5. Hope that helps!
42.21 or 84.42
84.42 or 42.21
Since we are talking for the sum of digits, then we are talking about 2-digit numbers between 1 and 100, which are 90 numbers (10 to 99). From these numbers only half of them satisfy the above condition, that is 45 numbers. So 50% of 2-digit numbers between 1 and 100 have an odd sum of their digits.
2.1 is one example.
63 How did you get this answer? The tens digit must be six. The ones digit must be half that, therefore three.
seven and eight tenths. you have to change one half to five tenths and then add the whole numbers and then the fraction