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The first 5 digit number is 10,000 and the last is 99,999. Thus there are 90,000 numbers between that range. Half of them are odd & half are even. 45,000 each

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Q: How many 5 digit numbers are odd?
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How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?

5*5*4*4 = 400


What is the last digit in the product of the first 20 odd natural numbers?

5.


How many odd numbers with middle digit 5 are there between 40000 and 69999 with no digits repeated?

To find the number of odd numbers with the middle digit 5 between 40000 and 69999 with no repeated digits, we can break down the problem. Since the middle digit is fixed at 5, we have to choose the other four digits without repetition. For the first digit (thousands place), we have 2 options (4 or 6). For the last digit (units place), we have 5 options (1, 3, 7, 9, 0). For the hundreds place and ten-thousands place, we have 8 and 7 options respectively. Therefore, the total number of odd numbers meeting the criteria is 2 * 8 * 7 * 5 = 560.


How do you divide 30 into 5 odd numbers?

You cannot. The sum of 5 odd numbers is always odd. 30 is not odd.


How many four odd numbers are possible such that the hundred digit is two more than tens digit?

I think the question means to ask for "four-digit" odd numbers, and left out a word. Each candidate is of the form (T H N U), and we're told that (H = N + 2). ' T ' can be: 1, 2, 3, 4, 5, 6, 7, 8, 9 = 9 possibilities. For each of these ... ' H N ' can be : 97, 86, 75, 64, 53, 42, 31, and 2,0 = 8 possibilities. For each of these ... ' U ' can be: 1, 3, 5, 7, 9 = 5 possibilities. So the total number of possibilities is: (9 x 8 x 5) = 360different 4-digit odd numbers with the hundreds digit greater by two than the tens digit.

Related questions

How many 5 digit odd numbers are possible without ending in 0?

All of them. There are roughly 45,000 5-digit odd numbers. None of them end in 0.


How many 4 digit numbers have only odd numbers?

To find the number of 4-digit numbers with only odd digits, we need to consider the options for each digit. Since odd digits are 1, 3, 5, 7, and 9, there are 5 choices for each digit. Therefore, the total number of 4-digit numbers with only odd digits is calculated as 5 x 5 x 5 x 5 = 625. So, there are 625 4-digit numbers that have only odd numbers.


How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?

5*5*4*4 = 400


How many odd numbers with middle digit 5 are there between 40000 and 69999 with no digits repeated?

To find the number of odd numbers with the middle digit 5 between 40000 and 69999 with no repeated digits, we can break down the problem. Since the middle digit is fixed at 5, we have to choose the other four digits without repetition. For the first digit (thousands place), we have 2 options (4 or 6). For the last digit (units place), we have 5 options (1, 3, 7, 9, 0). For the hundreds place and ten-thousands place, we have 8 and 7 options respectively. Therefore, the total number of odd numbers meeting the criteria is 2 * 8 * 7 * 5 = 560.


What is the smallest 5 digit number that all numbers are odd?

11111


Is it true that some numbers divisible by 5 are odd numbers?

50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.


What are all three-digit odd numbers whose digit sum is 9?

1, 3, and 5.


What is the last digit in the product of the first 20 odd natural numbers?

5.


How many 3-digit numbers are made up entirely of odd digits?

125 (5 to the third power). Each digit can be one of 5 (1/3/5/7/9).


What is the value of the digit in the hundreds place if 5 digit number are odd numbers?

As an example, 13579 the number 5 is in the hundreds place and has the value of 500. It does not matter whether the numbers are odd or even.


How many four-digit odd numbers are possible if the left digit cannot be zero?

9 x 10 x 10 x 5 = 45000


Is the number 4361 odd or even?

oddOdd numbers are integers which are not multiples of 2 or numbers with the last digit of 1, 3, 5, 7 and 9.The last digit of 4361 is 1 so it is an odd numbers.The last digit of even numbers can be 0, 2, 4, 6, and 8.