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What is the last digit in the product of the first 20 odd natural numbers?
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
How do you divide 30 into 5 odd numbers?
You cannot. The sum of 5 odd numbers is always odd. 30 is not odd.
How many odd numbers with middle digit 5 are there between 40000 and 69999 with no digits repeated?
To find the number of odd numbers with the middle digit 5 between 40000 and 69999 with no repeated digits, we can break down the problem. Since the middle digit is fixed at 5, we have to choose the other four digits without repetition. For the first digit (thousands place), we have 2 options (4 or 6). For the last digit (units place), we have 5 options (1, 3, 7, 9, 0). For the hundreds place and ten-thousands place, we have 8 and 7 options respectively. Therefore, the total number of odd numbers meeting the criteria is 2 * 8 * 7 * 5 = 560.
How many four odd numbers are possible such that the hundred digit is two more than tens digit?
I think the question means to ask for "four-digit" odd numbers, and left out a word. Each candidate is of the form (T H N U), and we're told that (H = N + 2). ' T ' can be: 1, 2, 3, 4, 5, 6, 7, 8, 9 = 9 possibilities. For each of these ... ' H N ' can be : 97, 86, 75, 64, 53, 42, 31, and 2,0 = 8 possibilities. For each of these ... ' U ' can be: 1, 3, 5, 7, 9 = 5 possibilities. So the total number of possibilities is: (9 x 8 x 5) = 360different 4-digit odd numbers with the hundreds digit greater by two than the tens digit.
How many 5 digit odd numbers are possible without ending in 0?
All of them. There are roughly 45,000 5-digit odd numbers. None of them end in 0.
What is the last digit in the product of the first 20 odd natural numbers?
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
How many 4 digit numbers have only odd numbers?
To find the number of 4-digit numbers with only odd digits, we need to consider the options for each digit. Since odd digits are 1, 3, 5, 7, and 9, there are 5 choices for each digit. Therefore, the total number of 4-digit numbers with only odd digits is calculated as 5 x 5 x 5 x 5 = 625. So, there are 625 4-digit numbers that have only odd numbers.
How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
What is the smallest 5 digit number that all numbers are odd?
11111
How many 4 digit numbers can you build if the number must be odd odd digits can be repeated and even digits cannot be repeated?
To form a 4-digit odd number, the last digit must be one of the odd digits (1, 3, 5, 7, 9), giving us 5 choices. For the first three digits, we can use odd digits freely (repeating allowed), giving us 5 choices for the first digit and 5 choices for the second digit. The third digit must be an even digit (0, 2, 4, 6, 8), but cannot repeat; therefore, we have 5 choices for the first digit and 4 choices for the second digit. Thus, the total number of valid 4-digit odd numbers is calculated as (5 \times 5 \times 5 \times 5 = 625).
Is it true that some numbers divisible by 5 are odd numbers?
50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.
What are all three-digit odd numbers whose digit sum is 9?
1, 3, and 5.
How many 3-digit numbers are made up entirely of odd digits?
125 (5 to the third power). Each digit can be one of 5 (1/3/5/7/9).
How many 2 digit odd numbers can be formed using the digits 123456789 without repitition?
To form a two-digit odd number using the digits 123456789 without repetition, the unit's digit must be an odd number. The available odd digits are 1, 3, 5, 7, and 9, giving us 5 options for the unit's place. For the ten's place, we can choose any of the remaining 8 digits. Therefore, the total number of two-digit odd numbers is (5 \times 8 = 40).
How many times does the digit 3 appear in the first 40 odd numbers?
Well, honey, the digit 3 appears in every odd number that ends in 3, 13, 23, 33, and so on up to 39. So, in the first 40 odd numbers, the digit 3 appears 4 times. Math doesn't have to be a drag, darling!
What is the value of the digit in the hundreds place if 5 digit number are odd numbers?
As an example, 13579 the number 5 is in the hundreds place and has the value of 500. It does not matter whether the numbers are odd or even.
