5*5*4*4 = 400
5.
To find the number of odd numbers with the middle digit 5 between 40000 and 69999 with no repeated digits, we can break down the problem. Since the middle digit is fixed at 5, we have to choose the other four digits without repetition. For the first digit (thousands place), we have 2 options (4 or 6). For the last digit (units place), we have 5 options (1, 3, 7, 9, 0). For the hundreds place and ten-thousands place, we have 8 and 7 options respectively. Therefore, the total number of odd numbers meeting the criteria is 2 * 8 * 7 * 5 = 560.
You cannot. The sum of 5 odd numbers is always odd. 30 is not odd.
I think the question means to ask for "four-digit" odd numbers, and left out a word. Each candidate is of the form (T H N U), and we're told that (H = N + 2). ' T ' can be: 1, 2, 3, 4, 5, 6, 7, 8, 9 = 9 possibilities. For each of these ... ' H N ' can be : 97, 86, 75, 64, 53, 42, 31, and 2,0 = 8 possibilities. For each of these ... ' U ' can be: 1, 3, 5, 7, 9 = 5 possibilities. So the total number of possibilities is: (9 x 8 x 5) = 360different 4-digit odd numbers with the hundreds digit greater by two than the tens digit.
All of them. There are roughly 45,000 5-digit odd numbers. None of them end in 0.
To find the number of 4-digit numbers with only odd digits, we need to consider the options for each digit. Since odd digits are 1, 3, 5, 7, and 9, there are 5 choices for each digit. Therefore, the total number of 4-digit numbers with only odd digits is calculated as 5 x 5 x 5 x 5 = 625. So, there are 625 4-digit numbers that have only odd numbers.
5*5*4*4 = 400
To find the number of odd numbers with the middle digit 5 between 40000 and 69999 with no repeated digits, we can break down the problem. Since the middle digit is fixed at 5, we have to choose the other four digits without repetition. For the first digit (thousands place), we have 2 options (4 or 6). For the last digit (units place), we have 5 options (1, 3, 7, 9, 0). For the hundreds place and ten-thousands place, we have 8 and 7 options respectively. Therefore, the total number of odd numbers meeting the criteria is 2 * 8 * 7 * 5 = 560.
11111
50% of numbers divisible by 5 are even, the other 50% are odd. If the single's digit of a number is 5, then the number is divisible by 5 and odd. For example, 25. However, if the single's digit of a number is 0, then the number is divisible by 5 and even. For example, 20.
1, 3, and 5.
5.
125 (5 to the third power). Each digit can be one of 5 (1/3/5/7/9).
As an example, 13579 the number 5 is in the hundreds place and has the value of 500. It does not matter whether the numbers are odd or even.
9 x 10 x 10 x 5 = 45000
oddOdd numbers are integers which are not multiples of 2 or numbers with the last digit of 1, 3, 5, 7 and 9.The last digit of 4361 is 1 so it is an odd numbers.The last digit of even numbers can be 0, 2, 4, 6, and 8.