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What are two ways of adding together 19 49 and 99 using Roman numerals throughout both calculations?
19 = XIX
49 = XLIX
99 = XCIX
Expected result is 167 = CLXVII
Method 1: Convert subtractive pairs so IV becomes IIII, XL becomes XXXX and XC becomes LXXXX. Then sort values in descending order of value, grouping C, X and I in groups of 5, and L and V in groups of 2, then reduce these groups so that IIIII becomes V, VV becomes X, XXXXX becomes L and LL becomes C.
XIX + XLIX + XCIX =
XVIIII + XXXXVIIII + LXXXXVIIII =
L + XXXXX + XXXX + VV + V + IIIII + IIIII + II =
L + XXXXX + XXXX + VV + VV + V + II =
L + XXXXX + XXXXX + X + V + II =
LL + L + X + V + II =
C + L + X + V + II =
CLXVII
Method 2: Expand all symbols into positive and negative symbols, sort by absolute value, cancel out any similar values with opposing signs. Convert higher values to lower values as required.
XIX + XLIX + XCIX =
X - I + X - X + L - I + X - X + C - I + X =
C + L + X + X - X + X - X + X - I - I - I =
C + L + X + X - I - I - I =
C + L + X + V + V - I - I - I =
C + L + X + V + I + I + I + I + I - I - I - I =
C + L + X + V + I + I =
CLXVII
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In Roman numerals what is the sum of x c c c x c I v?
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What are two different ways of adding together 1776 plus 199 plus 145 but working out both calculations entirely in Roman numerals?
Notwithstanding today's rules now governing the Roman numeral system that were introduced during the Middle Ages inasmuch that there exist credible evidence to suggest that the ancient Romans would have worked out the required calculations as follows:-MDCCLXXVI+CLXXXXVIIII+CXXXXV = MMCXX => 1776+199+145 = 2120VXXCCMMI+ICC+VCL = MMCXX => (2001-225)+(200-1)+(150-5) = 2120Note that the above calculations are fairly simple and straightforward but for more complicated calculations the Romans would have made use of an abacus calculating device.QED
What are two ways of adding 1776 plus 999 and two ways of subtracting 1776 minus 999 completely in Roman numerals?
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What is cmxclx in roman numerals?
The Roman numeral "CMXCLX" can be broken down as follows: CM is 900, XC is 90, and LX is 60. Adding these values together, CMXCLX equals 900 + 90 + 60, which totals 1050. Therefore, CMXCLX represents the number 1050 in Roman numerals.
How would you actually add together in two different ways 19 49 and 1999 using only Roman numerals throughout both calculations giving convincing reasons why?
I expect a Roman would notice that 1999 is only I less than MM, so he would used MM plus the others, take-away one I. Similarly for the others. So you have MM+XX+L less III = MMLXVII. In two different ways: take off the III before adding LXX or take it off afterwards instead.
