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What are two ways to add 1999 and 666 using Roman numerals throughout both calculations giving reasons why?
Under todays rules governing the Roman numeral system, which had nothing to do with the Romans themselves because they were introduced after the Dark Ages, 1999 is now officially considered to be MCMXCIX which is rather remarkable inasmuch that mathematical integration with other numerals is hardly possible.
But there is evidence to suggest that the Romans would have actually calculated the equivalent of 1999 on an abacus counting device as MDCCCCLXXXXVIIII and then probably abridged it to IMM (2000-1) in written format thus facilitating the speed and ease of addition as follows:-
IMM+DCLXVI = MMDCLXV (2000-1)+(666) = (2665)
Alternatively:-
MDCCCCLXXXXVIIII+DCLXVI = MMDCLXV (1999)+(666) = (2665)
Note that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M
Roman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1
QED
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How would you actually add together in two different ways 19 49 and 1999 using only Roman numerals throughout both calculations giving convincing reasons why?
I expect a Roman would notice that 1999 is only I less than MM, so he would used MM plus the others, take-away one I. Similarly for the others. So you have MM+XX+L less III = MMLXVII. In two different ways: take off the III before adding LXX or take it off afterwards instead.
How should the New Year of 2014 be correctly expressed using Roman numerals in two different ways if one of them is not MMXIV giving reasons?
MMXIIII as the alternate (on clocks for example) version of number 4 is IIII
How do you work out 1776 plus 1999 in Roman numerals giving reasons for your answer?
Today we write out 1999 in Roman numerals as MCMXCIX because of changes made to the rules governing the Roman numeral system during the Middle Ages and to add these numerals to MDCCLXXVI is almost impossible. But the Romans themselves would have calculated 1999 on an abacus counting device as MDCCCCLXXXXVIIII and probably simplified them to IMM by placing I to both sides of the numerals. So: MDCCLXXVI + (-I+MM) = MMMDCCLXXV (3775)
How would you actually add 1776 and 1999 in two different ways using Roman numerals throughout both calculations giving reasons why in step by step stages?
Officially in accordance with todays guidelines governing the Roman numeral system 1999 when converted into Roman numerals is MCMXCIX which makes addition with other numerals an almost impossible task.But during the classical Roman period the equivalent of 1999 would have been calculated on an abacus counting device as MDCCCCLXXXXVIIII which then can be abridged to IMM (2000-1) in written form thus facilatating the speed and ease of addition as follows:-MDCCLXXVI+IMM = MMMDCCLXXV (1776)+(2000-1) = (3775)Alternatively:-MDCCLXXVI+MDCCCCLXXXXVIIII = MMMDCCLXXV (1776)+(1999) = (3775)Note that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=MRoman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1QED
What is four point five in Roman numerals giving reasons for your answer?
4.5 = SV (-0.5+5=4.5) Because: 4.5 = IIIIS which can be simplified to SV And: II*IIIIS = VIIII which can be simplified to IX Roman Numerals: M=1000, D=500, C=100, L=50, X=10, V=5, I=1 and S=1/2
Is MCMXCIX bigger or smaller than IMM in Roman numerals or are they both the same giving reasons why?
They are both the same because in todays modern notation of Roman numerals the equivalent of 1999 is MCMXCIX which means 1000+900+90+9 = 1999 But the ancient Romans would have probably gone for the simpler version of IMM which means 2000-1 = 1999
How would you actually add together in two different ways 998001 and 1999 using only Roman numerals throughout both calculations giving dual reasons why?
Today we would convert 998,001 and 1,999 into Roman numerals as (CMXCVIII)I and MCMXCIX respectively which are incompatible with each other for the purpose of addition.But notwithstanding todays configuration of these numerals inasmuch that there is evidence to suggest that the ancient Romans would have calculated the equivalent of these numbers in either of the following formats:-(IIM)I+IMM = (M) => [1,000,000-2,000]+1+[2,000-1] = 1,000,000Alternatively:-(DCCCCLXXXXVIII)I+MDCCCCLXXXXVIIII = (M) => 998,001+1,999 = 1,000,000Remember: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=MRoman numerals: M=1000, D=500, C=100, L=50, X+10, V=5 and I=1Note that numerals within brackets indicate multiplication by a thousand and that the practice of placing a bar above a numeral to indicate multiplication by a thousand was introduced during the Middle Ages along with other rules and regulations now governing todays Roman numeral system.QED
What are the reasons for giving children's literature to children?
In a poem
Why should your calculations never be more precise than your measurements?
Your calculations can be more precise, but the final result should be rounded, to avoid giving the impression that it is more exact than is justified by the measurements.
What is ironic about a math teacher giving the wrong amount to a waiter?
Math teachers are expected to make accurate calculations.
What is the correct way to write out 19 in Roman numerals if it is not XIX giving reasons why?
XIX is the correct roman numeral for 19.Another Answer:-Nowadays it is XIX but in ancient Rome it was IXX because its Latin word is undeviginti meaning one from twenty and there is no Latin word for the equivalent of XIX
What are two different ways of correctly adding together 666 and 999 using only Roman numerals throughout both calculations giving clear reasons why?
The rules governing the Roman numeral system were set in the Middle Ages and as a result today we would write out 999 in Roman numerals as CMXCIX which makes it almost impossible for them to intermingle with other numerals.But the Romans in the past would have probably calculated the equivalent of 999 on an abacus counting device as DCCCCLXXXXVIIII and changed it to IM in written form which makes addition straightforward as follows:-DCLXVI+IM = MDCLXV => (666)+(1000-1) = (1665)Alternatively:-DCLXVI+DCCCCLXXXXVIIII = MDCLXV +> (666)+(999) = (1665)Note that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=MRoman numerals: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1QED
