Best Answer

Assuming that the face cards are given numbers (J = 11, Q = 12, K = 13 and A = 1), then the prime numbers that are possible are 2, 3, 5, 7, 11, 13. There are six primes out of 13 possible numbers, giving a probability of 6/13, or about .462 (46.2%).

Note: This ignores the fact that there are four of each number in the deck. It's easy to show that the fours cancel out of the fraction. 24/52 = (6*4)/(13*4) = 3/13.

Q: What are your chances of drawing a card with a prime number in FULL Deck of cards without a joker?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

It is 8/52 or 2/13

52 cards in a pack. 4 two's, 4 three's, hence 8 chances of drawing one of the desired cards out of the 52. 8/52 = 2/13

Provided the choice is totally random, because there are 52 cards in a standard pack, the chances of drawing a club is 13/52 (25%) so, therefore the chances of not getting a club are 75% or 39/52

In a deck of 52 cards, there are 4 chances to get an ace and 4 chances to get a ten so there are 8 chances to get an ace or a ten So the probability is 8/52=2/13=0.15

It is (4/52)*(3/51)*(2/50)*(1/49) = 1/270,725 = 0.0000037 approx.

Related questions

7.7% or 4 chances out of 52.

It is 8/52 or 2/13

52 cards in a pack. 4 two's, 4 three's, hence 8 chances of drawing one of the desired cards out of the 52. 8/52 = 2/13

Number of cards in a deck = 52 Number of cards that are heart = 13 Therefore number of cards that are not heart = 52-13 = 39 Probability of not drawing a heart = 39/52 or 3/4

Provided the choice is totally random, because there are 52 cards in a standard pack, the chances of drawing a club is 13/52 (25%) so, therefore the chances of not getting a club are 75% or 39/52

In a deck of 52 cards, there are 4 chances to get an ace and 4 chances to get a ten so there are 8 chances to get an ace or a ten So the probability is 8/52=2/13=0.15

number of cards that are 10 =4 number of cards in a standard deck =52 Probability of drawing a 10 =4/52 = 1/13

It is (4/52)*(3/51)*(2/50)*(1/49) = 1/270,725 = 0.0000037 approx.

The answer depends on:whether or not the cards are drawn at random,whether or not the cards are replaced before drawing another,how many cards are drawn.If 45 cards are drawn, without replacement, the event is a certainty.

The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement. Without that information it is not possible to give a meaningful answer.

! in 4, as the four suits have an equal number of cards.

1 in 132,600 for a deck of 52 cards (without jokers) 1 in 148,824 for a deck of 54 cards (with jokers)