Aprox. 0.018%There are 4 queens in a regular deck of 52 cards.The probability of drawing a queen on the first draw is: P(Q1) = 4/52.The probability of drawing a queen on the second draw given that the first card wasa queen is: P(Q2│Q1) = 3/51.The probability of drawing a queen on the third draw given that the first two cardswere queens is: P(Q3│(Q2UQ1)) = 2/50.The probability of drawing 3 queens on the first 3 cards drawn from a deck of cardsis: P(Q1UQ2UQ3) = (4/52)∙(3/51)∙(2/50) = 1.80995... x 10-4 ≈ 0.00018 ≈ 0.018%
4/52 X 3/51 x 2/50.
In a deck of 52 cards, there are four suits. Each suit contains an ace and the numbers two through ten as well as a Jack, Queen, and King. In a modern deck, there are twelve face cards in all.
P(8) AND P(8) = 4/52 * 3/51 = 12/2652 = 0.00452.
The probability of drawing three diamonds from a standard deck of 52 cards is (13 in 52) times (12 in 51) times (11 in 50), or 1716 in 132600, or about 0.01294.
The probability of drawing three queens from a deck of cards is (4 in 52) times (3 in 51) times (2 in 50), or 24 in 132,600 or 1 in 5,525.
The probability of drawing 3 cards, all with the value of 9, from a standard 52 card deck, is ~0.018%.
It is a possible but unlikely event.
The probability of drawing 2 sixes from a deck of 52 cards is (4 in 52) times (3 in 51) which is (12 in 2652) or (1 in 221) or about 0.004525.
The probability of drawing 3 sixes from a deck of 52 cards is (4 in 52) times (3 in 51) times (2 in 50) which is (24 in 132600) or (1 in 5525) or about 0.0001810.
Aprox. 0.018%There are 4 queens in a regular deck of 52 cards.The probability of drawing a queen on the first draw is: P(Q1) = 4/52.The probability of drawing a queen on the second draw given that the first card wasa queen is: P(Q2│Q1) = 3/51.The probability of drawing a queen on the third draw given that the first two cardswere queens is: P(Q3│(Q2UQ1)) = 2/50.The probability of drawing 3 queens on the first 3 cards drawn from a deck of cardsis: P(Q1UQ2UQ3) = (4/52)∙(3/51)∙(2/50) = 1.80995... x 10-4 ≈ 0.00018 ≈ 0.018%
4/52 X 3/51 x 2/50.
In a deck of 52 cards, there are four suits. Each suit contains an ace and the numbers two through ten as well as a Jack, Queen, and King. In a modern deck, there are twelve face cards in all.
The queen of spades is looking in a different way than all other queens.
P(8) AND P(8) = 4/52 * 3/51 = 12/2652 = 0.00452.
Likelihood is 1/52 or approximately 1.9%. This is based on: (1) a standard deck has 52 cards, and (2) a standard deck has only one king of clubs. So the chance of drawing that one card out of all 52 cards, on one try is: 1 divided by 52.
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.