2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
7, R 16
7/16 - 1/4... Make the 1/4 into 16ths by multiplying BOTH numbers by 4 - You now have... 7/16 - 4/16 which is 3/16
32
14 = 2*7 49 = 7*7 So 1, -1, 7, -7 all go into both 14 and 49.
16 and 13 both go into any multiple of 208 .
both these number go into the number 112
how many times can 7 go into 49? easy...
2X + 7 = 5X + 16 subtract 2X from both sides 7 = 3X + 16 subtract 16 from both sides -9 = 3X divide both sides by 3 -3 = X check 2(-3) + 7 = 5(-3) + 16 1 = 1 checks
16 and remainder 2
126 ÷ 16 = 7 14/16 = 7⅞ = 7.875
both numerator and denominator are divisible by 16 so 16/112 = 1/7
16/7 = 2 with a remainder of 2
7 x 16 = 112
7, R 16
7 and 8 both go into 56
It is an equation in the form of: n/16 +7 = 10 and the value of n is 48