Nothing !... 23 is a Prime number - only divisible by 1 and itself !
56 , can be evenly divided by 56 (1x) and 28 (2x)
yes Because 56 divided by 2 is 28
A factor of a number is any number that the original number can divide by evenly. In this case, 56 divided by 32 is 1 with remainder 24. It has not divided evenly. Therefore 32 is not a factor of 56.
56
none
14
8
56 divided by 23 is 2,43478260869565. U figure out the remainder.
If a number can be divided evenly by anything other than '1' and itself, then it's composite.56 can be divided evenly by 1, 2, 4, 7, 8, 14, 28, and 56. I guess it's composite.
1, 2, 4, 7, 8, 14, 28, 56.
161 can be divided evenly by: 1, 7, 23, 161.
8 goes into 56 evenly, and the answer is 7. That means 7 X 8=56 with no remainders.