STOP at an intersection without a traffic light.
Assuming you mean a sum of 4, there are three ways this can be done: (1, 3), (2, 2) and (3, 1).
Aquiel can select 4 books out of 10 best sellers, which can be done in 10 choose 4 ways, also denoted as "10C4" or "10 choose 4". This would result in 210 different ways for Aquiel to select and read the 4 books.
To form a 4-person relay team from 8 track runners, we first choose 4 runners from the 8, which can be done in ( \binom{8}{4} = 70 ) ways. Then, we can arrange these 4 runners in ( 4! = 24 ) different ways. Therefore, the total number of arrangements is ( 70 \times 24 = 1680 ). Thus, there are 1,680 ways to arrange 8 track runners on a 4-person relay team.
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In Five Card Stud, a flush consists of five cards of the same suit. To calculate the number of ways to achieve a flush, you first choose one suit from the four available suits, which can be done in 4 ways. Then, you select 5 cards from the 13 available in that suit, which can be done in ( \binom{13}{5} = 1,287 ) ways. Therefore, the total number of ways to get a flush in Five Card Stud is ( 4 \times 1,287 = 5,148 ).
5 ways in a straight line: GGBBBB, BGGBBB, BBGGBB, BBBGGB, BBBBGG
Vitamin treatment usually is done in three ways
4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.4*3*2*1 = 24 ways.
4 Possible ways
There are 4! or factorial(4) = 24 ways.
Since there are 4 letters, they can be arranged 4! ways (4*3*2*1) or 24 ways.
Five people are to be arranged in a row to have their picture taken. In how many ways can this be done?