Yes because 56/63 = 8/9 in its lowest terms
63
8/9
divide both by the highest factor (8 in this case) answer is 8 over 7
63...so it would be 56/63 and 36/63
36/63 + 56/63 = 92/63 or 1 and 29/63
To find how many eights are in 63, you divide 63 by 8. The result is 7 with a remainder of 7, meaning there are 7 complete eights in 63, which equals 56. Thus, 63 contains 7 eights, with 7 left over.
9/8 or 11/8
1.125 or 1 1/8
1/7 (one over seven. divide the 8 and 56 by 8).
= 1.31746032 8/9 + 3/7 = 56/63 + 27/63 = 83/63 = 1 20/63 (or 1.31746 in decimal form).
8 can go into 63 a total of 7 times, as 8 multiplied by 7 equals 56, which is the largest multiple of 8 that is less than 63. If you divide 63 by 8, you get 7 with a remainder of 7. Therefore, the full answer is that 8 goes into 63 seven times, with a remainder.
The GCF is "7"... for 63 and 56 7 x 8 = 56 7 x 9 = 63