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What are the six trigonometric functions of 180 degrees?
sin(180) = 0 cos(180) = -1 tan(180) = 0 cosec(180) is not defined sec(180) = -1 cot(180) is not defined.
Find value of trigonometric functions of quadrantal angle?
sin 0=13/85
How is tan equal to undefined?
Tan of pi/2 + k*pi radians, for integer k, is not defined since tan = sin/cos and the cosine of these angles is 0. Since divsiion by 0 is not defined, the tan ratio is not defined.
What are the 6 trig functions for 0 degrees 90 degrees 180 degrees 270 degrees?
sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.
What is the solution to sec plus tan equals cos over 1 plus sin?
sec + tan = cos /(1 + sin) sec and tan are defined so cos is non-zero. 1/cos + sin/cos = cos/(1 + sin) (1 + sin)/cos = cos/(1 + sin) cross-multiplying, (1 + sin)2 = cos2 (1 + sin)2 = 1 - sin2 1 + 2sin + sin2 = 1 - sin2 2sin2 + 2sin = 0 sin2 + sin = 0 sin(sin + 1) = 0 so sin = 0 or sin = -1 But sin = -1 implies that cos = 0 and cos is non-zero. Therefore sin = 0 or the solutions are k*pi radians where k is an integer.
Which is smaller sin 0 or sin 200?
i think sin 200 is smaller than sin 0.. because sin 200= - sin 20.. sin 0 = 0 of course 0 > - sin 20
What is sin of 0?
sin(0) is 0
Why tan A 90 degree is not solve?
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
What are the 6 trig functions for a -180 degree angle?
Sin= 0 Cos= -1 Tan= 0 Csc= undef. Sec= -1 Cot= undef.
What is sin of -pi?
sin(-pi) = sin(-180) = 0 So the answer is 0
Sin and cosine values of 0?
sin 0 = 0 cos 0 = 1
What is limit in calulus?
Some functions are not defined for selected values of their argument. But, as you calculate the value of the function nearer and nearer to these selected values, you get a consistent result - whichever side you approach the critical value from.For example, sin(x)/x [where the angle x is measured in radians] is not defined for x = 0 since it would be 0/0 which is undefined. However, as x approaches 0, from the negative or positive side, the value of the function gets closer and closer to 1. In this case, the limit of sin(x)/x, as x approaches 0, is said to be 1.
