Any number can be the next number. It is easy to find a rule based on a polynomial of order 2 such that the first two numbers are 1 and 247, and followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
So, if you want the next number to be 1, use the rule t(n) = -246n^2 + 984n - 737
You want 9, use the rule t(n) = -242n^2 + 972n - 729
You want 99, use the rule t(n) = -197n^2 + 837n - 639
You want 765, use the rule t(n) = 136n^2 - 162n + 27
and so on.
The next number in the sequence is... 64
The next number is 25 but there are the sequence is infinite so there can be no end to the sequence.
Consecutive terms in the sequence are being divided by -2. Therefore, -1 / -2 = 1/2 or 0.5.
22.5, 33.75, 50.625...
The next four number in the sequence are... 4,5,5 & 6
The reciprocal of -247 is -1/247(Because -247 = -247/1
what are the next 2 numbers in this sequence: 20 , 1 ,18 ,4 ,9 ,1
25 is the next number that appears in that sequence.
If you mean: 5000 1000 200 then it is 40 because 1/5 of 200 is 40
The next number in this sequence is 13112221.
The sequence is generated using cubes, or n^3. The next number in the sequence will be 4^3, or 256.
The next term in the sequence (not the next sequence) is 76.It is obtained by using n= 6 int(n) = (29n4 - 338n3 + 1363n2 - 2158n + 1128)/24 for n = 1, 2, 3, etc