81
The sequence given consists of the cubes of consecutive integers: (1^3 = 1), (2^3 = 8), (3^3 = 27), and (4^3 = 64). Therefore, the next number in the sequence is (5^3 = 125).
The next one is 125.
The sequence is generated using cubes, or n^3. The next number in the sequence will be 4^3, or 256.
125 (the sequence is successive numbers cubed)
456789
27
The next one is 125.
The sequence is generated using cubes, or n^3. The next number in the sequence will be 4^3, or 256.
125 (the sequence is successive numbers cubed)
8
4
456789
This is a peculiar number sequence which follows the following rule: +7, -4, +8, -3, +9, -2... The next few functions would be +10, -1, +11, -0 And thus the next few numbers in the sequence would be 17+10=27, 27-1=26, and so on. The sequence in total goes 2, 9, 5, 13, 10, 19, 17, 27, 26, 37, 37.
243
64. It's the sequence f(n) = n^3
3263442
343.