125 (the sequence is successive numbers cubed)
64 It is a series of cubes 13, 23, 33, 43, 53 etc
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.
The numbers are perfect cubes, so d will also be a perfect cube.
125 13 23 43 53...
These are perfect cubes (of 1, 2 and 3) so the next two are 64 and 125
the cube root of 125 is 5, the cube root of 64 is 4, the cube root of 27 is 3, the cube root of 8 is 2, and the cube root of 1 is 1.
In the list of cubes, the next number is 216.
125 (the sequence is successive numbers cubed)
1 8 27 64 125 216 343
They are perfect cubes: 13, 23, 33, 43, and 53.
They are the cubes of the natural numbers, starting with 1.
64. It's the sequence f(n) = n^3
343.
64 It is a series of cubes 13, 23, 33, 43, 53 etc
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.
The numbers are perfect cubes, so d will also be a perfect cube.