491
379, but it does not complete the sequence which is infinite.
1 + (4) = 5 5 + (4x3) = 17 17 + (4x3x3) = 53 53 + (4x3x3x3) = 161 161 + (4x3x3x3x3) = ?
485
485
335
The next number is 485.
Try: 161+324 = 485 would seem to fit the pattern
each number is 3 times the last plus 2
The seed number is 1, thereafter each number is 2 + (3 x the previous number). 2 + 3x1 = 5 2 + 3x5 = 17 2 + 3x17 = 53 2 + 3x53 = 161 2 + 3x161 = 485
485
To get the number to complete the sequence, multiply the first number to 3 and then add 2 to get the next number. Given 1, 5, 17, 53, 161 ____Solution:1 x 3 (+2) = 55 x 3 (+2) = 1753 x 3 (+2) = 161161 x 3 (+2) = 485Therefore, the number to complete the sequence is 485.
Here is one way to describe this sequence: a(0)=1 a(n) = 3*a(n-1) + 2 a(n) = 2*3^n - 1 So we have: 1, 5, 17, 53, 161, 485, 1457, 4373, 13121, 39365, 118097, 354293, 1062881, 3188645, 9565937, 28697813, 86093441, ...