0
If you're referring to the curve y = x2, then the shape it describes is called a parabola. It looks somewhat like an infinitely tall letter "V" with a curved bottom.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Describe the curve x2 plus y2 equals 25?
A circle, centre (0,0), radius = 5
What are the possible values of k in the line y equals kx -2 which is tangent to the curve y equals x squared -8x plus 7?
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
How do you find the exact value of the gradient of the curve with equation y equals 1 divide by 4 minus x2 at the point where x equals 1 over 2?
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
What does the Graph of x2 25 look like?
If f(x) = x2 + 25, then to plot f(x) on a graph would give you a parabolic curve extending infinitely upward with a minimum value of 25, and it's vertex at the point (0, 25).
What are the possible values of k when y equals kx -2 which is tangent to the curve of y equals x squared -8x plus 7 showing work?
The gradient to the curve y = x2 - 8x + 7 is dy/dx = 2x - 8The gradient of the tangent to the curve is, therefore, 2x - 8.The gradient of the given line is kTherefore k = 2x - 8. That is, k can have ANY value whatsoever.Another Answer:-If: y = kx-2 and y = x2-8x+7Then: x2-8x+7 = kx-2 => x2-8x-kx+9 = 0Use the discriminant of: b2-4ac = 0So: (-8-k)2-4*1*9 = 0Which is: (-8-k)(-8-k)-36 = 0 => k2+16k+28 = 0Using the quadratic equation formula: k = -2 or k = -14 which are the possible values of k for the straight line to be tangent with the curve
What is the function for y equals x2?
f(x) = x2 This describes a parabolic curve, with it's vertex at the point (0, 0)
What is the gradient of the curve x2 xy y24 at the point 01?
1/6
What is the gradient of the tangent to the curve at x equals 2 if Y equals x2?
Gradient to the curve at any point is the derivative of y = x2 So the gradient is d/dx of x2 = 2x. When x = 2, 2x = 4 so the gradient of the tangent at x = 2 is 4.
Describe the curve x2 plus y2 equals 25?
A circle, centre (0,0), radius = 5
How do you graph x2?
If you're trying to plot the curve y = x2, you can do so by plugging a few small values in as x, finding their corresponding y values, and marking those points on a graph. Then draw a "curve of best fit" that intersects all of those points. This particular curve would be a parabola moving upwards, with a focal point of (0, 0).
What are the possible values of k in the line y equals kx -2 which is tangent to the curve y equals x squared -8x plus 7?
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
Why do people study Transformation geometry?
Every process or body has originated from the idea of a parent body or process. We are all in some way a transformation of our parent bodies. In mathematics its objects and shapes and rules and formulas started with some basic parent shape or body or rule etc. Transformations describes how the new curve is transformed from its parent curve. Example the parent curve for y = x2 +6 is the curve y = x2. Transformation geometry is a tool with which change and deviation has become a social expression away from the standard.
How do you prove that the line y equals x-4 is tangent to the curve of x squared plus y squared equals 8?
equation 1: y = x-4 => y2 = x2-8x+16 when both sides are squared equation 2: x2+y2 = 8 Substitute equation 1 into equation 2: x2+x2-8x+16 = 8 => 2x2-8x+8 = 0 If the discriminant of the above quadratic equation is zero then this is proof that the line is tangent to the curve: The discriminant: b2-4ac = (-8)2-4*2*8 = 0 Therefore the discriminant is equal to zero thus proving that the line is tangent to the curve.
What is the direction opening of y equals -3x2 plus 6x-13?
The coefficient of x2 is -3 which is negative. Therefore the curve is downward opening.
How does the inequality symbol affect the graph of an inequality with two variables?
Instead of the answer being a curve, it is a region. For example, if y > x2 + 4, the answer is not the parabola y = x2 + 4. Instead it is the region above the parabola (as if the bowl were filled with something.)
For what point x y on curve y equals 1-x2 is sum x plus y a maximum?
3
How do you find the exact value of the gradient of the curve with equation y equals 1 divide by 4 minus x2 at the point where x equals 1 over 2?
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
