i believe it was a z
ya it was
the pilgrams started it and the only indian who could speak inglish, helped them survive
because the indians introduced it to the pilgrams
The X Factor UK began on 4th September 2004.
Jay-Z started in 1996.
logbase5 of x =z x=5^z
If x = y and y = z then x = z
There are 8 different subsets. The null set. {x} {y} {z} {x y} {x z} {y z} {x y z}
No, but I can name words that have both Z and X in them: Oxydize Zax Zanax Zenix I couldn't find any that started with x and had a Z in it.
To determine the value of the expression x-a x-b x-c x-z, we need to consider the factors of the expression. Since each letter of the alphabet (excluding x) is subtracted from x in one of the factors, there are a total of 26 factors. This means that the expression must be expanded to include all 26 letters of the alphabet as factors, resulting in x-a x-b x-c ... x-z. Therefore, the value of the expression is x-a x-b x-c ... x-z.
Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x & y & z are inputs.
if X(Z) is a Z-transform of x[n] and X(Z) is causal then the initial value theorem states that the lim as z tends to infinity for X(Z) must eqaul x(0).
If z = 3, what is 5 x (6 – z)?