1 × 52
2 × 26
4 × 13
2 × 2 × 13
Multiplying each number by 4 gives you the (decimated) .52 answer.
This is a combinations question. There are (52 C 13) possible hands. This is 52!/((13!)((52-13)!)) = 635013559600
This questions can be rewritten as 52 choose 6 or 52C6. This is the same as (52!)/(6!(52-6)!) (52!)(6!46!) (52*51*50*49*48*47)/(6*5*4*3*2*1) 14658134400/720 20358520 There are 20,358,520 combinations of 6 numbers in 52 numbers. This treats 1,2,3,4,5,6 and 6,5,4,3,2,1 as the same combination since they are the same set of numbers.
There are 43 combinations of various quantities of quarters (0, 1 or 2), dimes (0 to 5), nickels (0 to 10) and pennies (2 to 52) that make 52 cents.
There are 4 aces and 16 tens (including face cards) in a standard 52-card deck of cards, so there are 64 different blackjack combinations. There are 52!/(50!2!) = 1326 different two-card combinations in the deck, so the odds are 64/1326 = 0.048, or slightly less than 5%.
There are several combinations, but this is one: 23 + 29 = 52.
Dividing distance travelled by speed, and multiplying by 60, gives 26/30 x 60 = 52 minutes.
It won't work for all numbers. I tried with 1 and got a 0.230769...
55 x 54 x 53 x 52 x 51 x 50 = 20,872,566,000 possible combinations This includes counting combinations such as 1,2,3,4,5,6 and 1,2,3,4,6,5 and 6,5,4,3,2,1 and 4,2,3,1,5,6 as different. In a lottery, these are all considered to be the same. To get the number of combinations without regard to order, divide that number by 6!=6x5x4x3x2 which is 28,989,675
Do you mean 1 to the power of 52? If that is so, 1^52 is 1, since all you are doing is multiplying fifty-two ones, which of course equals one.
You work this out by dividing 4 by 52 then multiplying by 100 4/52= 0.0769 0.0769 * 100 = 7.69 % This could be rounded to 8 % if the significant digits in the answer are restricted.
Finding 52 percent of a number is the same as multiplying the number by 0.52. In this instance, 86 x 0.52 = 44.72.