1,3,5,7,9
127.869 In ones place is 7 In tenths place is 8 In tens place is 2
8500
The 8 in 128.90 is in the place value column which is immediately before the decimal point - this is the ones column. The digit in 6.3457 which is in the ones place (immediately before the decimal point) is 6.
2,5 or 8
13
The thousands place is the fourth place to the left of the decimal point (which in a whole number is "hiding" after the ones digit at the end); in 86931 it is the 6.
If you mean: 8,832 then its value is two = 2
The hundreds digit is 2; the tens digit is 5; the ones digit is 8; the tenths digit is 1; the hundredths digit is 7; the thousandths digit is 6.
The 0, in the tens' place has a value of 0. The digit 1 is in the thousandths' place - a much smaller place value but, its value is 1 times a thousandth, which is bigger than 0.
The places are always the same no matter what the digits are. The value is obtained by multiplying the place times the digit. Starting from the right, the places in an 8-digit number are ones, tens, hundreds, thousands, ten thousands, hundred thousands, millions and ten millions.
Ten million is 10,000,000 so its place column is 8 to the left of the decimal point (which in a whole number is "hiding" after the last, ones, digit). In 375,426,198,000 the ten millions digit is 2.
No. To test if a number is divisible by 8: * first all multiples of 8 are even, so the number must be even; * then: add 4 times the hundreds digit to twice the tens digit to the ones digit - if this sum is divisible by 8, then so is the original number. As the test can be applied to the sum, repeating this summing until a single digit remains, only if this single digit is 8 is the original number divisible by 8. For 100: 4x1 + 2x0 + 0 = 4 which is not 8, so 100 is not divisible by 8.