18 numbers are there
There are two single-digit numbers less than 10 which are cubes of whole numbers. These are 13 (one cubed = 1) and 23 (two cubed = 8).
Five.The five numbers are 11, 12, 15, 24, 36
It doesn't matter if you know that the largest three-digit prime number is 997 or that its cube root is 9.98998998. If you include zero in the whole numbers, the answer will be zero.
72 is less than 75, just as 2 is less than 5.When the first digit is the same (7 and 7 in this case) then you can just look at the last digit for whole numbers.
There are no three-digit numbers that equal 17. In fact, there are no numbers with more or less than two digits that equal 17. In fact, in the whole infinite supply of numbers, there is only one single number that equals 17. That number is . . . . . . . 17 .
the set of whole numbers less than 0
Not sure what you're asking, but here are some examples of numbers that have a tens digit less than the ones digit: 13, 205, 1367, 29.632
No. The whole numbers are {0, 1, 2, 3, ...}. There are none less than 0.
The same as whole numbers. When rounding to a specific place, take a look at the digit immediately to the right of the target. If that digit is 4 or less, zero everything to the right of the target out. If that digit is 5 through 9, increase the target by one and zero everything to the right of it out. If the target is a 9, increasing it will turn it to zero and increase the digit to the left of the target by one.
There are 14 whole numbers in that range divisible by 7. There are 19 whole numbers in that range with a 7 in their digits. Three overlap so there is a total of 30 whole numbers with either characteristic.
40, 51, 62, 73, 84, and 95