371/3 = 123 and 2/3
371/5 = 74.2
371/7 = 53
371/9 = 41 and 2/9
six and five eights times two and one third = 371/246 5/8 = [(8 * 6)+5]/8 = (48+5)/8 = 53/82 1/3 = [(3 * 2)+1]/3 = (6+1)/3 = 7/353/8 * 7/3 = 371/24
371 It will not divide by '2' as it is not even . It will not divide by '5' as it does not end in '5' or '0'. It will not divide by '9' as the sum of the digits is '2'. So try '3' 3)371 = 123.6666.... Not a whole number, so does not divide by '3' Try '7' 7)371 = 53 No, so 371 is NOT a prime number because it has the factors of of '7' and 53'. which are both prime numbers.
371/7 = 53
1-8-7-3-6-5-4-2
How about: 7*53 = 371 or 1*371 = 371
371 is divisible by 1, 7, 53, 371.
53 x 7 = 371
21
It is: 7*53 = 371
7 - 35 (5 x 7), 56 (8 x 7), 84 (12 x 7)
35- 1, 5, 3545- 1, 3, 5, 15, 45the greatest common factor between them is 5* * * * *Why the selective factorisation? 7 divides 35, 9 divides 45?The factors of 45 are 1, 3, 5, 9, 14, and 45.The factors of 35 are 1, 5, 7, and 35.The greatest common factor of 35 and 45 is 5.
371 = 7 x 53