Both 5 and 7 are prime numbers, so the only number that could go into both evenly would be 1.
70
Factor them both. 1 x 5 = 5 1 x 7 = 7 Discard the common factor (1) and combine the remaining ones 5 x 7 = 35 35 is the lowest (least) number that both 5 and 7 will go into evenly.
1, 5, 7, 35.
5, 7, and 3 go into 105.
Both numbers add up to 7
the biggest number that can go into both 10 and 35 is 5. so 5 goes into 10, 2 times and 5 goes into 35, 7 times so the answer is 2/7
-12
Their LCM is 280
5a - 5 = 7 + 2a ( subtract 2a from both sides) 3a - 5 = 7 (add 5 to both sides) 3a = 12 ( divide both sides by 3) a = 4
7+8x-5 = 8x+7-5x Subtract 7 from both sides: 8x-5 = 8x-5x Subtract 8x from both sides: -5 = -5x Divide both sides by -5: x = 1 So the equation implies x = 1
There are an infinite number of positive integers divisible by 3, 5, and 7. This is because there is no limit to numbers and they go on indefinitely in both a positive and a negative direction.