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All direct variation graphs are linear and they all go through the origin.

Q: What do all direct variation graphs have in common?

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I have recently been doing all these direct variation problems but not every linear relationship is a direct variation... But every direct variation is a linear relation!

No, not all m & m's weigh the same. There is variation in all processes. This variation (called common cause) will affect the weight of the m & m's.

Do all linear graphs have proportional relationship

Polynomials have graphs that look like graphs of their leading terms because all other changes to polynomial functions only cause transformations of the leading term's graph.

No.

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I have recently been doing all these direct variation problems but not every linear relationship is a direct variation... But every direct variation is a linear relation!

The graph of a quadratic equation is a parabola.

All graphs are graphical graphs because if they were not graphical graphs they would not be graphs!

No, not all m & m's weigh the same. There is variation in all processes. This variation (called common cause) will affect the weight of the m & m's.

A direct variation is when the value of K in multiple proportions is all divisible by the same number for example: XY=(1)(10) K=10 XY=(2)(20) K=40 XY=(3)(30) K=90 XY=(4)(40) K=160 In this situation the constant (K) of each proportion is divisible by 10 making the multiple equations a direct variation.

Most graphs: Pie charts, bar graphs, histograms, scatter graphs can all be used.

All variable costs are those costs which vary with the variation in the volume of production as well as direct costs are those costs which are directly attributable to any specific unit of product so it may be accepted that all direct costs are variable costs but fixed costs may also be direct cost.

they all compare different amounts

Do all linear graphs have proportional relationship

Polynomials have graphs that look like graphs of their leading terms because all other changes to polynomial functions only cause transformations of the leading term's graph.

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No.