They are the first five terms of the polynomial:
67,574n4 - 657,854.5n3 + 2,261,386n2 - 3,192,345.5n +1,521,268 for n = 1, 2, 3, 4 and 5
6, 28, 496, 8128
6, 28, 496, 8128
6, 28, 496 and 8128 are the first four Perfect numbers.
6, 28, 496, 8128.
The first perfect numbers are 6, 28, 496, 8128.More information here: http://en.wikipedia.org/wiki/Perfect_numberThe first perfect numbers are 6, 28, 496, 8128.More information here: http://en.wikipedia.org/wiki/Perfect_numberThe first perfect numbers are 6, 28, 496, 8128.More information here: http://en.wikipedia.org/wiki/Perfect_numberThe first perfect numbers are 6, 28, 496, 8128.More information here: http://en.wikipedia.org/wiki/Perfect_number
8128 / 2 = 2^6 x 127 8128 / 1 = 8128 8128 / 2 = 4064 8128 / 4 = 2032 8128 / 8 = 1016 8128 / 16 = 508 8128 / 32 = 254 8128 / 64 = 127 1 + 2 + 4 + 8 + 16 + 32 + 64 + 127 + 254 + 508 + 1016 + 2032 + 4064 + 8128 = 16252
Yes. The next perfect numbers are 496 and 8128.
8128 They're known as perfect numbers.
No. The first four perfect numbers are 6, 28, 496, 8128.
You get 8128!!! It is PERFECT!!
8128 = 26*127
I have this question in algebra 2 and the book said 496, 8128