Let us go step by step
Period = 2 pi ./l/g
Or frequency = 1/2pi * ./g/l
Or 2 pi frequency = angular frequency = ./g/l
As we reduce the length by 4 times i.e 1/4 l then we have angular frequency doubled.
Hence reduce the length to 0.25 l
The frequency of a pendulum varies with the square of the length.
The frequency of a pendulum is inversely proportional to the square root of its length.
A longer pendulum will have a smaller frequency than a shorter pendulum.
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
9.7m
The frequency of a pendulum varies with the square of the length.
The frequency of a pendulum is inversely proportional to the square root of its length.
A longer pendulum will have a smaller frequency than a shorter pendulum.
decrease by a factor of 4
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
For relatively small oscillations, the frequency of a pendulum is inversely proportional to the square root of its length.
The pendulum frequency is dependent upon the length of the pendulum. The torque is the turning force of the pendulum.
The factors that affect a simple pendulum are; length; angular displacement; and mass of the bong.
It doesn't. Only the length of the pendulum and the strength of the gravitational field alter the period/frequency.
9.7m
The formula for the frequency of the pendulum is w2=g/l if you wish to double your period w1, you want to have w2 = 2*w1 The needed length of the pendulum is then l2 = g / w22 = g /(4 * w12) = 0.25 * g / w12 = 0.25 * l1 l2 / l1 = 1/4 You must shorten the length of the pendulum to 1/4 of its former size.
The lower the frequency, the larger mass and longer length, The higher the frequency, the smaller the mass, and shorter the length.