Even numbers : they can be written 2n
2n1+2n2+....+2nm = 2(n1+n2+....+nm) so it's always an even number
2n1x 2n2x....x2nm = 2(n1+n2+....+nm) which is always an even number
Odd numbers: they canbe written 2n+1
(2n1+1) + (2n2+1) + ....+ (2nm +1) = 2(n1+n2+....+nm) + m which is even if m is even and odd if m is odd, so it depend of the number of terms
(2n1+1) x (2n2+1) x ....x (2nm +1) is always odd cause the last term of the expansion is always +1 and other terms have at least 2 as factor
They are 1 and 15.
you have to add
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
It means to give the reason of something, (numbers,sums,differences, and problems.)
To divide decimals the partial sums method requires that numbers are separated into individual portions. The separated numbers are then solved in long division until eliminated.
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
They are 1 and 15.
you can make at least 25 sums
To give mathematical completeness; it enables all sums to be solvable, (even if this just means proving that they have no answer) in the same way that inventing "negative numbers", "zero" and "imaginary numbers" enable all maths to be solvable. (Not that all sums have answers).
you have to add
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
No.
Infinitely many. 12+11, 13+10, 14+9, ... , 22+1, 23+0, 24+(-1), 25+(-2), ... and then you have sums with numbers to one decimal place (dp) such as 11.6+11.4, and so on. Not forgetting numbers to 2 dp, 3, dp, 4, dp, ... , infinitely many dp. But these are only sums of two numbers. There are sums of 3 numbers, 4 numbers, ... infinitely many.
It means to give the reason of something, (numbers,sums,differences, and problems.)
average function
11
2 + 3 = 5