The prime factors of 42 are 2, 3 and 7. I'd have to see the rectangles to know what to write in them.
It is: 2*3*7 = 42
The prime factors of 42 are 2, 3, and 7.
Prime factors of 42: 2, 3 and 7 Prime factors of 56: 2 and 7
The prime factors of 28 are 2 and 7. The prime factors of 42 are 2, 3, and 7.
2, 3 and 7 are the prime factors of 42. 2 and 23 are the prime factors of 184.
The prime factors of 42 are: 2,3,7
The prime factorization of 42 is 2x3x7. The prime factors are 2, 3, and 7. There are eight total factors of 42: 1, 2, 3, 6, 7, 14, 21, and 42.
42 = 2 * 3 * 7the prime factors of 42 are 1,2,3,7the product of these numbers is... 1x2x3x7 = 42
The prime numbers (factors) of 42 are: 2,3,7
42 - The prime factors are: 2, 3 and 7660 - The prime factors are: 2, 3, 5 and 11
To find the HCF of two numbers you first have to write them as their prime factors: 14 = 2x7 42 = 2x3x7 The next step is to identify any common prime factors. In this case both numbers have a 2 and a 7 as prime factors. Multiply these together and you get: 2x7 = 14 Thus the HCF of 14 and 42 is 14.
The prime factors are: 2, 3, 7