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Q: What are the factors of x squared minus 4?

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3x2 - 11x - 4 = (x-4)(3 x + 1)

The factors of 6x^2 = 23x = 4 are (6x + 1)(x - 4)

There are no rational factors.

(x - 5)(x + 4)

That factors to (x - 14)(x + 14)

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This expression factors as x -1 quantity squared.

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(x + 2)(x - 4)

It is the difference of squares. (x-4) and (x+4) <--- answer

Factors of -8 are -1 & 8, -2 & 4, -4 & 2 and -8 & 1. Only -4 & 2 add to -2 so factors are (x + 2)(x - 4)

x2-10x-24 = (x+2)(x-12) when factored

x(x + 3)(x - 4)

Assuming that is x squared minus 16: x2 - 16 = (x + 4)(x - 4) (The difference of two squares.)

That factors to (x - 3)(x + 6)

That factors to (x - 5)(x - 1)

x = ? 42 = x squared minus x

(X-5)(X+4)=0 so X-5=0 -----X=5 and X=4=0 so X=-4 it factors to (X-5)(X+4) so X=5,-4

x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).

(x - 16)(x + 2) x = 16 or -2

(x-1)(x-4)

(2x - 3)(x + 2)

4(x - 1)(x + 1)

It is x^2 -x -12 is (x+3)(x-4) when factored

1/x4