2 eyes on the road and 2 hands on the wheel
2NH4NO3->2N2+O2+4H2O
n * 2n = 2n2
2n2 / n = 2n
2(n2+3n-54) 2(n+9)(n-6)
If the question is, "What is the solution to 2n2 + 6n - 108 = 0 ?"The equation can be factored : 2n2 + 6n - 108 = (2n - 12)(n + 9) = 0If 2n -12 = 0 then n = 6If n + 9 = 0 then n = -9The roots of this equation are n = 6 and n = -9.
2n2 + 15n + 7 = 2n2 + n + 14n + 7 = (2n2 + n) + (14n + 7) = n(2n + 1) + 7(2n + 1) = (2n + 1)(n + 7)
2NH4NO3->2N2+O2+4H2O
Maximum of 2n2, where n is the energy level.
n * 2n = 2n2
yes
M5h 2n2
(n - 4)(2n + 3)
2n2 / n = 2n
The maximum is 18. This follows the law maximum = 2n2 where n = shell number, ie in this case n=3, 2n2=18.
Well the formula for calculating the maximum amount of electrons that can be held in a shell of an atom is: 2(n)2 N being the shell number. For example: 2(1)2= 2 (the maximum amount of electrons for shell number 1)
The balance is 2N2 +2O2= 4NO
Yes I can.