7u = -6v - 44 + 3u = 14v + 64
The first two give: 4u = -6v - 44
and the first and third give: 7u = 14v + 64
Then 7*the first of these minus 4 times the second give:
28u - 28u = -42v -308 - 56v - 256 = -98v -564
So 98v = -564 and so v = -282/49 =
And then 7u = 14*(-282/49) + 64 = -116/7
so that u = -116/49
Solution:
u = -116/49 = -2.3673 to 4 dp
v = -282/49 = -5.7551 to 4 dp
Another Answer:-
If the question was meant to be: 7u = -6v-44 and 3u = 14v+64
Then by a process of multplication and elimination the solution to this simultaneous equation would work out as: u = -2 and v = -5
The equation has no solution. Since if you combine like terms, you get 0=-10 which isn't true, there are no solutions to the equation.
14v
The answer is a number that can be substituted in place of 'v' and makes the statement true.Here's a way to find it:-10 = 14v + 14Subtract 14 from each side:-24 = 14vDivide each side by 14:-24/14 = vSimplify the ugly fraction on the left side:v = -24/14 = -12/7 = -(1 and 5/7)
12-14v
It is equivalent to: 35-14v
From the alternator to the battery should be 14v
Yes. From 13.8 to 15.5 volts is normal.
3 and 5/72 = 3 and 1/14v by dividing 5 on the numerator or denominator
The battery is 12 volts but the alternator generates about 13-14v to charge the battery.
Do you mean 1400v + 2v^7 (is 2v to the power 7)? When you differentiate, e.g. 2v^7, you bring the 7 to the front and reduce the power by 1. If so the answer is 1400 + 7*2v^6 (where * means multiply) or 1400 + 14v^6
Assuming that the numbers immediately succeeding each "v" in the expression are intended to be exponents, in this type of problem only the coefficients of those terms with the same exponents can be added. Therefore in the sum, the coefficient of "v" will be (3 + 15 - 14) = 4; the coefficient of "v2" will be (-11 + 5) = -6; and the coefficient of "v3" will be (8 - 4) = 4. The final answer is therefore 4 v3 - 6 v2 + 4 v.
Couldn't tell you, they both put out 12.8/14v and 27/6.7W And in size and look they are absolutely identical